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244150112137 is a prime number
BaseRepresentation
bin1110001101100001111…
…0110000111110001001
3212100012020111202120211
43203120132300332021
513000004412042022
6304054440121121
723432160466051
oct3433036607611
9770166452524
10244150112137
11945a8411988
123b3994661a1
131a03c131099
14bb6191a561
15653e483e77
hex38d87b0f89

244150112137 has 2 divisors, whose sum is σ = 244150112138. Its totient is φ = 244150112136.

The previous prime is 244150112099. The next prime is 244150112179. The reversal of 244150112137 is 731211051442.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 214284742281 + 29865369856 = 462909^2 + 172816^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-244150112137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 244150112099 and 244150112108.

It is not a weakly prime, because it can be changed into another prime (244150112737) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122075056068 + 122075056069.

It is an arithmetic number, because the mean of its divisors is an integer number (122075056069).

Almost surely, 2244150112137 is an apocalyptic number.

It is an amenable number.

244150112137 is a deficient number, since it is larger than the sum of its proper divisors (1).

244150112137 is an equidigital number, since it uses as much as digits as its factorization.

244150112137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6720, while the sum is 31.

Adding to 244150112137 its reverse (731211051442), we get a palindrome (975361163579).

The spelling of 244150112137 in words is "two hundred forty-four billion, one hundred fifty million, one hundred twelve thousand, one hundred thirty-seven".