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244202013131 is a prime number
BaseRepresentation
bin1110001101101110010…
…0110000000111001011
3212100022212011121100212
43203123210300013023
513000111203410011
6304103532351335
723433360601646
oct3433344600713
9770285147325
10244202013131
119462474096a
123b3b291554b
131a049b0382b
14bb6878aa5d
156543cd708b
hex38db9301cb

244202013131 has 2 divisors, whose sum is σ = 244202013132. Its totient is φ = 244202013130.

The previous prime is 244202013073. The next prime is 244202013157. The reversal of 244202013131 is 131310202442.

244202013131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 244202013131 - 214 = 244201996747 is a prime.

It is a super-2 number, since 2×2442020131312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 244202013097 and 244202013106.

It is not a weakly prime, because it can be changed into another prime (244202010131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122101006565 + 122101006566.

It is an arithmetic number, because the mean of its divisors is an integer number (122101006566).

Almost surely, 2244202013131 is an apocalyptic number.

244202013131 is a deficient number, since it is larger than the sum of its proper divisors (1).

244202013131 is an equidigital number, since it uses as much as digits as its factorization.

244202013131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 244202013131 its reverse (131310202442), we get a palindrome (375512215573).

The spelling of 244202013131 in words is "two hundred forty-four billion, two hundred two million, thirteen thousand, one hundred thirty-one".