Base | Representation |
---|---|
bin | 100011100010010011101… |
… | …111100001101001100001 |
3 | 22122110021120201011121122 |
4 | 203202103233201221201 |
5 | 310002224123232343 |
6 | 5105503142302025 |
7 | 341300351434604 |
oct | 43422357415141 |
9 | 8573246634548 |
10 | 2442020133473 |
11 | 86172277a418 |
12 | 335343727915 |
13 | 14938762b3cb |
14 | 862a163a33b |
15 | 437c88eb068 |
hex | 23893be1a61 |
2442020133473 has 2 divisors, whose sum is σ = 2442020133474. Its totient is φ = 2442020133472.
The previous prime is 2442020133437. The next prime is 2442020133479. The reversal of 2442020133473 is 3743310202442.
Together with previous prime (2442020133437) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1296152649169 + 1145867484304 = 1138487^2 + 1070452^2 .
It is a cyclic number.
It is not a de Polignac number, because 2442020133473 - 222 = 2442015939169 is a prime.
It is not a weakly prime, because it can be changed into another prime (2442020133479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1221010066736 + 1221010066737.
It is an arithmetic number, because the mean of its divisors is an integer number (1221010066737).
Almost surely, 22442020133473 is an apocalyptic number.
It is an amenable number.
2442020133473 is a deficient number, since it is larger than the sum of its proper divisors (1).
2442020133473 is an equidigital number, since it uses as much as digits as its factorization.
2442020133473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 35.
The spelling of 2442020133473 in words is "two trillion, four hundred forty-two billion, twenty million, one hundred thirty-three thousand, four hundred seventy-three".
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