2442112121133 has 32 divisors (see below), whose sum is σ = 3621727872000. Its totient is φ = 1626372772848.

The previous prime is 2442112121101. The next prime is 2442112121147. The reversal of 2442112121133 is 3311212112442.

2442112121133 is a `hidden beast` number, since 2 + 4 + 421 + 1 + 21 + 211 + 3 + 3 = 666.

2442112121133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 2442112121133 - 2⁵ = 2442112121101 is a prime.

It is a super-2 number, since 2×2442112121133² (a number of 26 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 2442112121097 and 2442112121106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2442112128133) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 137598166 + ... + 137615912.

It is an arithmetic number, because the mean of its divisors is an integer number (113178996000).

Almost surely, 2^{2442112121133} is an apocalyptic number.

It is an amenable number.

2442112121133 is a deficient number, since it is larger than the sum of its proper divisors (1179615750867).

2442112121133 is a wasteful number, since it uses less digits than its factorization.

2442112121133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22798 (or 22792 counting only the distinct ones).

The product of its digits is 2304, while the sum is 27.

Adding to 2442112121133 its reverse (3311212112442), we get a palindrome (5753324233575).

The spelling of 2442112121133 in words is "two trillion, four hundred forty-two billion, one hundred twelve million, one hundred twenty-one thousand, one hundred thirty-three".