Base | Representation |
---|---|
bin | 100011100010100000010… |
… | …111111000101001110011 |
3 | 22122110211100110010210102 |
4 | 203202200113320221303 |
5 | 310003142400240201 |
6 | 5105540152223015 |
7 | 341305533552206 |
oct | 43424027705163 |
9 | 8573740403712 |
10 | 2442232040051 |
11 | 861821354a21 |
12 | 3353a269aa6b |
13 | 1493bc4c400b |
14 | 862c183b93d |
15 | 437dc30826b |
hex | 238a05f8a73 |
2442232040051 has 2 divisors, whose sum is σ = 2442232040052. Its totient is φ = 2442232040050.
The previous prime is 2442232039991. The next prime is 2442232040077. The reversal of 2442232040051 is 1500402322442.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2442232040051 - 218 = 2442231777907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2442232039996 and 2442232040023.
It is not a weakly prime, because it can be changed into another prime (2442232040251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1221116020025 + 1221116020026.
It is an arithmetic number, because the mean of its divisors is an integer number (1221116020026).
Almost surely, 22442232040051 is an apocalyptic number.
2442232040051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2442232040051 is an equidigital number, since it uses as much as digits as its factorization.
2442232040051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15360, while the sum is 29.
Adding to 2442232040051 its reverse (1500402322442), we get a palindrome (3942634362493).
The spelling of 2442232040051 in words is "two trillion, four hundred forty-two billion, two hundred thirty-two million, forty thousand, fifty-one".
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