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244305014113 is a prime number
BaseRepresentation
bin1110001110000110110…
…1101010110101100001
3212100121000222121011001
43203201231222311201
513000314040422423
6304122052152001
723436051233236
oct3434155526541
9770530877131
10244305014113
11946778a2046
123b421308601
131a065258264
14bb7831d78d
15654cd80cad
hex38e1b6ad61

244305014113 has 2 divisors, whose sum is σ = 244305014114. Its totient is φ = 244305014112.

The previous prime is 244305014101. The next prime is 244305014131. The reversal of 244305014113 is 311410503442.

Together with next prime (244305014131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 180746570449 + 63558443664 = 425143^2 + 252108^2 .

It is a cyclic number.

It is not a de Polignac number, because 244305014113 - 221 = 244302916961 is a prime.

It is not a weakly prime, because it can be changed into another prime (244305014153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122152507056 + 122152507057.

It is an arithmetic number, because the mean of its divisors is an integer number (122152507057).

Almost surely, 2244305014113 is an apocalyptic number.

It is an amenable number.

244305014113 is a deficient number, since it is larger than the sum of its proper divisors (1).

244305014113 is an equidigital number, since it uses as much as digits as its factorization.

244305014113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 244305014113 its reverse (311410503442), we get a palindrome (555715517555).

The spelling of 244305014113 in words is "two hundred forty-four billion, three hundred five million, fourteen thousand, one hundred thirteen".