Base | Representation |
---|---|
bin | 10110110000010100… |
… | …100000011010011101 |
3 | 2100001210000002222020 |
4 | 112300110200122131 |
5 | 400014322032031 |
6 | 15120244010353 |
7 | 1523321043252 |
oct | 266024403235 |
9 | 70053002866 |
10 | 24433002141 |
11 | a3a887a159 |
12 | 489a6909b9 |
13 | 23c4c24222 |
14 | 127ad51429 |
15 | 980023096 |
hex | 5b052069d |
24433002141 has 4 divisors (see below), whose sum is σ = 32577336192. Its totient is φ = 16288668092.
The previous prime is 24433002127. The next prime is 24433002149. The reversal of 24433002141 is 14120033442.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 24433002141 - 25 = 24433002109 is a prime.
It is a super-2 number, since 2×244330021412 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (24433002149) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4072167021 + ... + 4072167026.
It is an arithmetic number, because the mean of its divisors is an integer number (8144334048).
Almost surely, 224433002141 is an apocalyptic number.
It is an amenable number.
24433002141 is a deficient number, since it is larger than the sum of its proper divisors (8144334051).
24433002141 is an equidigital number, since it uses as much as digits as its factorization.
24433002141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8144334050.
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 24433002141 its reverse (14120033442), we get a palindrome (38553035583).
The spelling of 24433002141 in words is "twenty-four billion, four hundred thirty-three million, two thousand, one hundred forty-one".
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