Base | Representation |
---|---|
bin | 1110001110100111010… |
… | …1011000100011110011 |
3 | 212100221112100022022122 |
4 | 3203221311120203303 |
5 | 13001103430113011 |
6 | 304143400224455 |
7 | 23442324243404 |
oct | 3435165304363 |
9 | 770845308278 |
10 | 244441254131 |
11 | 947377961a8 |
12 | 3b45aa6b12b |
13 | 1a08754a059 |
14 | bb8c4659ab |
15 | 6559ce33db |
hex | 38e9d588f3 |
244441254131 has 2 divisors, whose sum is σ = 244441254132. Its totient is φ = 244441254130.
The previous prime is 244441253993. The next prime is 244441254149. The reversal of 244441254131 is 131452144442.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 244441254131 - 222 = 244437059827 is a prime.
It is a super-2 number, since 2×2444412541312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 244441254091 and 244441254100.
It is not a weakly prime, because it can be changed into another prime (244441254331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122220627065 + 122220627066.
It is an arithmetic number, because the mean of its divisors is an integer number (122220627066).
Almost surely, 2244441254131 is an apocalyptic number.
244441254131 is a deficient number, since it is larger than the sum of its proper divisors (1).
244441254131 is an equidigital number, since it uses as much as digits as its factorization.
244441254131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 61440, while the sum is 35.
Adding to 244441254131 its reverse (131452144442), we get a palindrome (375893398573).
The spelling of 244441254131 in words is "two hundred forty-four billion, four hundred forty-one million, two hundred fifty-four thousand, one hundred thirty-one".
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