Base | Representation |
---|---|
bin | 110111101110110111011111… |
… | …100110110111001010010010 |
3 | 1012010212121010010221102110202 |
4 | 313232313133212313022102 |
5 | 224111413403432401002 |
6 | 2225151245031055202 |
7 | 102425563406321000 |
oct | 6756673746671222 |
9 | 1163777103842422 |
10 | 245113240122002 |
11 | 71111a39a6166a |
12 | 235a8708211502 |
13 | a6a0105493545 |
14 | 44757890d9a70 |
15 | 1d50e57c9b502 |
hex | deeddf9b7292 |
245113240122002 has 32 divisors (see below), whose sum is σ = 438740900400000. Its totient is φ = 102605542364304.
The previous prime is 245113240121999. The next prime is 245113240122017. The reversal of 245113240122002 is 200221042311542.
It is a super-2 number, since 2×2451132401220022 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4154713877 + ... + 4154772872.
It is an arithmetic number, because the mean of its divisors is an integer number (13710653137500).
Almost surely, 2245113240122002 is an apocalyptic number.
245113240122002 is a deficient number, since it is larger than the sum of its proper divisors (193627660277998).
245113240122002 is an equidigital number, since it uses as much as digits as its factorization.
245113240122002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8309486815 (or 8309486801 counting only the distinct ones).
The product of its (nonzero) digits is 7680, while the sum is 29.
Adding to 245113240122002 its reverse (200221042311542), we get a palindrome (445334282433544).
The spelling of 245113240122002 in words is "two hundred forty-five trillion, one hundred thirteen billion, two hundred forty million, one hundred twenty-two thousand, two".
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