Base | Representation |
---|---|
bin | 110111101110111110000101… |
… | …001101101010010100111011 |
3 | 1012010220021101002202022022012 |
4 | 313232332011031222110323 |
5 | 224112022400224012422 |
6 | 2225154414550120135 |
7 | 102426233606126111 |
oct | 6756760515522473 |
9 | 1163807332668265 |
10 | 245120313500987 |
11 | 71114a39774a21 |
12 | 235a9b6105004b |
13 | a6a0991a4bcb2 |
14 | 4475c5a6b7ab1 |
15 | 1d5121dc5c4e2 |
hex | deef8536a53b |
245120313500987 has 2 divisors, whose sum is σ = 245120313500988. Its totient is φ = 245120313500986.
The previous prime is 245120313500983. The next prime is 245120313501031. The reversal of 245120313500987 is 789005313021542.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 245120313500987 - 22 = 245120313500983 is a prime.
It is not a weakly prime, because it can be changed into another prime (245120313500981) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122560156750493 + 122560156750494.
It is an arithmetic number, because the mean of its divisors is an integer number (122560156750494).
Almost surely, 2245120313500987 is an apocalyptic number.
245120313500987 is a deficient number, since it is larger than the sum of its proper divisors (1).
245120313500987 is an equidigital number, since it uses as much as digits as its factorization.
245120313500987 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1814400, while the sum is 50.
The spelling of 245120313500987 in words is "two hundred forty-five trillion, one hundred twenty billion, three hundred thirteen million, five hundred thousand, nine hundred eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •