Base | Representation |
---|---|
bin | 1110010001010001001… |
… | …0001000011000110101 |
3 | 212102210011102202021000 |
4 | 3210110102020120311 |
5 | 13004033234330031 |
6 | 304342200513513 |
7 | 23466062541141 |
oct | 3442422103065 |
9 | 772704382230 |
10 | 245153433141 |
11 | 94a727a38a1 |
12 | 3b61947b899 |
13 | 1a16bc61a56 |
14 | bc18c90221 |
15 | 659c5be3e6 |
hex | 3914488635 |
245153433141 has 32 divisors (see below), whose sum is σ = 364769233920. Its totient is φ = 162726138432.
The previous prime is 245153433127. The next prime is 245153433163. The reversal of 245153433141 is 141334351542.
245153433141 is a `hidden beast` number, since 2 + 4 + 51 + 534 + 3 + 31 + 41 = 666.
It is a de Polignac number, because none of the positive numbers 2k-245153433141 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 245153433096 and 245153433105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (245153433101) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8822716 + ... + 8850458.
It is an arithmetic number, because the mean of its divisors is an integer number (11399038560).
Almost surely, 2245153433141 is an apocalyptic number.
It is an amenable number.
245153433141 is a deficient number, since it is larger than the sum of its proper divisors (119615800779).
245153433141 is a wasteful number, since it uses less digits than its factorization.
245153433141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29162 (or 29156 counting only the distinct ones).
The product of its digits is 86400, while the sum is 36.
Adding to 245153433141 its reverse (141334351542), we get a palindrome (386487784683).
The spelling of 245153433141 in words is "two hundred forty-five billion, one hundred fifty-three million, four hundred thirty-three thousand, one hundred forty-one".
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