Base | Representation |
---|---|
bin | 110111110010001101110001… |
… | …000101000110010101110011 |
3 | 1012011200120222101112222200121 |
4 | 313302031301011012111303 |
5 | 224124201101341332012 |
6 | 2225445055033031111 |
7 | 102451320015160105 |
oct | 6762156105062563 |
9 | 1164616871488617 |
10 | 245343314011507 |
11 | 711a05737440a8 |
12 | 23625217555497 |
13 | a6b8a102787ba |
14 | 448297337b575 |
15 | 1d56e21592a07 |
hex | df2371146573 |
245343314011507 has 2 divisors, whose sum is σ = 245343314011508. Its totient is φ = 245343314011506.
The previous prime is 245343314011489. The next prime is 245343314011513. The reversal of 245343314011507 is 705110413343542.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 245343314011507 - 211 = 245343314009459 is a prime.
It is a super-2 number, since 2×2453433140115072 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (245343314014507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122671657005753 + 122671657005754.
It is an arithmetic number, because the mean of its divisors is an integer number (122671657005754).
Almost surely, 2245343314011507 is an apocalyptic number.
245343314011507 is a deficient number, since it is larger than the sum of its proper divisors (1).
245343314011507 is an equidigital number, since it uses as much as digits as its factorization.
245343314011507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 604800, while the sum is 43.
The spelling of 245343314011507 in words is "two hundred forty-five trillion, three hundred forty-three billion, three hundred fourteen million, eleven thousand, five hundred seven".
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