2454010133 has 4 divisors (see below), whose sum is σ = 2488573728. Its totient is φ = 2419446540.

The previous prime is 2454010063. The next prime is 2454010147. The reversal of 2454010133 is 3310104542.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3310104542 = 2 ⋅1655052271.

It is a cyclic number.

It is not a de Polignac number, because 2454010133 - 2²⁰ = 2452961557 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2454010099 and 2454010108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2454010033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17281691 + ... + 17281832.

It is an arithmetic number, because the mean of its divisors is an integer number (622143432).

Almost surely, 2^2454010133 is an apocalyptic number.

It is an amenable number.

2454010133 is a deficient number, since it is larger than the sum of its proper divisors (34563595).

2454010133 is an equidigital number, since it uses as much as digits as its factorization.

2454010133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34563594.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 2454010133 is about 49537.9665811991. The cubic root of 2454010133 is about 1348.8348672277.

Adding to 2454010133 its reverse (3310104542), we get a palindrome (5764114675).

The spelling of 2454010133 in words is "two billion, four hundred fifty-four million, ten thousand, one hundred thirty-three".