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245401404342307 is a prime number
BaseRepresentation
bin110111110011000011110111…
…100010001000000000100011
31012011220010220210202112202221
4313303003313202020000203
5224131124034002423212
62225531503202251511
7102455444365634113
oct6763036742100043
91164803823675687
10245401404342307
1171213173171454
1223634529956b97
13a6c133a197cc5
1444856c436b043
151d586c1327807
hexdf30f7888023

245401404342307 has 2 divisors, whose sum is σ = 245401404342308. Its totient is φ = 245401404342306.

The previous prime is 245401404342217. The next prime is 245401404342317. The reversal of 245401404342307 is 703243404104542.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 245401404342307 - 231 = 245399256858659 is a prime.

It is a super-3 number, since 3×2454014043423073 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (245401404342317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122700702171153 + 122700702171154.

It is an arithmetic number, because the mean of its divisors is an integer number (122700702171154).

Almost surely, 2245401404342307 is an apocalyptic number.

245401404342307 is a deficient number, since it is larger than the sum of its proper divisors (1).

245401404342307 is an equidigital number, since it uses as much as digits as its factorization.

245401404342307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1290240, while the sum is 43.

Adding to 245401404342307 its reverse (703243404104542), we get a palindrome (948644808446849).

The spelling of 245401404342307 in words is "two hundred forty-five trillion, four hundred one billion, four hundred four million, three hundred forty-two thousand, three hundred seven".