Base | Representation |
---|---|
bin | 1110010010010000110… |
… | …0100100110110001101 |
3 | 212110110202210200211001 |
4 | 3210210030210312031 |
5 | 13010110111143201 |
6 | 304424455100301 |
7 | 23505514041061 |
oct | 3444414446615 |
9 | 773422720731 |
10 | 245420412301 |
11 | 9509a474229 |
12 | 3b692971691 |
13 | 1a1b236a89c |
14 | bc42509aa1 |
15 | 65b5c59301 |
hex | 3924324d8d |
245420412301 has 8 divisors (see below), whose sum is σ = 250058401560. Its totient is φ = 240782697792.
The previous prime is 245420412299. The next prime is 245420412359. The reversal of 245420412301 is 103214024542.
It can be written as a sum of positive squares in 4 ways, for example, as 63151187401 + 182269224900 = 251299^2 + 426930^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 245420412301 - 21 = 245420412299 is a prime.
It is a super-2 number, since 2×2454204123012 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 245420412301.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (245420412001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3115071 + ... + 3192883.
It is an arithmetic number, because the mean of its divisors is an integer number (31257300195).
Almost surely, 2245420412301 is an apocalyptic number.
It is an amenable number.
245420412301 is a deficient number, since it is larger than the sum of its proper divisors (4637989259).
245420412301 is an equidigital number, since it uses as much as digits as its factorization.
245420412301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 137375.
The product of its (nonzero) digits is 7680, while the sum is 28.
Adding to 245420412301 its reverse (103214024542), we get a palindrome (348634436843).
It can be divided in two parts, 245420 and 412301, that added together give a square (657721 = 8112).
The spelling of 245420412301 in words is "two hundred forty-five billion, four hundred twenty million, four hundred twelve thousand, three hundred one".
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