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245574122194201 is a prime number
BaseRepresentation
bin110111110101100100101110…
…010100011100010100011001
31012012111122201210212111210111
4313311210232110130110121
5224141441300240203301
62230143105545244321
7102504100451306533
oct6765445624342431
91165448653774714
10245574122194201
117127a444968a09
1223661ab07936a1
13a704704219278
14448dbcad62853
151d5ce2e582551
hexdf592e51c519

245574122194201 has 2 divisors, whose sum is σ = 245574122194202. Its totient is φ = 245574122194200.

The previous prime is 245574122194109. The next prime is 245574122194213. The reversal of 245574122194201 is 102491221475542.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 201958347552025 + 43615774642176 = 14211205^2 + 6604224^2 .

It is a cyclic number.

It is not a de Polignac number, because 245574122194201 - 231 = 245571974710553 is a prime.

It is not a weakly prime, because it can be changed into another prime (245574122194231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122787061097100 + 122787061097101.

It is an arithmetic number, because the mean of its divisors is an integer number (122787061097101).

Almost surely, 2245574122194201 is an apocalyptic number.

It is an amenable number.

245574122194201 is a deficient number, since it is larger than the sum of its proper divisors (1).

245574122194201 is an equidigital number, since it uses as much as digits as its factorization.

245574122194201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1612800, while the sum is 49.

The spelling of 245574122194201 in words is "two hundred forty-five trillion, five hundred seventy-four billion, one hundred twenty-two million, one hundred ninety-four thousand, two hundred one".