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2493156503051 is a prime number
BaseRepresentation
bin100100010001111011101…
…101010010111000001011
322211100021100210220020122
4210101323231102320023
5311321441031044201
65145201300213455
7345060512421314
oct44217355227013
98740240726218
102493156503051
11881383938785
1234323509a28b
13151146944066
1488952c5560b
1544cbce0ce1b
hex2447bb52e0b

2493156503051 has 2 divisors, whose sum is σ = 2493156503052. Its totient is φ = 2493156503050.

The previous prime is 2493156503039. The next prime is 2493156503081. The reversal of 2493156503051 is 1503056513942.

2493156503051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2493156503051 - 218 = 2493156240907 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2493156502993 and 2493156503011.

It is not a weakly prime, because it can be changed into another prime (2493156503081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1246578251525 + 1246578251526.

It is an arithmetic number, because the mean of its divisors is an integer number (1246578251526).

Almost surely, 22493156503051 is an apocalyptic number.

2493156503051 is a deficient number, since it is larger than the sum of its proper divisors (1).

2493156503051 is an equidigital number, since it uses as much as digits as its factorization.

2493156503051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486000, while the sum is 44.

The spelling of 2493156503051 in words is "two trillion, four hundred ninety-three billion, one hundred fifty-six million, five hundred three thousand, fifty-one".