Base | Representation |
---|---|
bin | 1001010010101000… |
… | …0111000111000001 |
3 | 20102211000201220221 |
4 | 2110222013013001 |
5 | 20101440122022 |
6 | 1051252303041 |
7 | 115543135522 |
oct | 22452070701 |
9 | 6384021827 |
10 | 2494067137 |
11 | 106a921611 |
12 | 597311a81 |
13 | 309932b93 |
14 | 199348849 |
15 | e8e57cc7 |
hex | 94a871c1 |
2494067137 has 2 divisors, whose sum is σ = 2494067138. Its totient is φ = 2494067136.
The previous prime is 2494067101. The next prime is 2494067141. The reversal of 2494067137 is 7317604942.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2489610816 + 4456321 = 49896^2 + 2111^2 .
It is a cyclic number.
It is not a de Polignac number, because 2494067137 - 211 = 2494065089 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2494067093 and 2494067102.
It is not a weakly prime, because it can be changed into another prime (2494067837) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1247033568 + 1247033569.
It is an arithmetic number, because the mean of its divisors is an integer number (1247033569).
Almost surely, 22494067137 is an apocalyptic number.
It is an amenable number.
2494067137 is a deficient number, since it is larger than the sum of its proper divisors (1).
2494067137 is an equidigital number, since it uses as much as digits as its factorization.
2494067137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 254016, while the sum is 43.
The square root of 2494067137 is about 49940.6361293086. The cubic root of 2494067137 is about 1356.1343400360.
The spelling of 2494067137 in words is "two billion, four hundred ninety-four million, sixty-seven thousand, one hundred thirty-seven".
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