25000411 has 2 divisors, whose sum is σ = 25000412. Its totient is φ = 25000410.

The previous prime is 25000373. The next prime is 25000427. The reversal of 25000411 is 11400052.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 25000411 - 2¹⁵ = 24967643 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 25000391 and 25000400.

It is not a weakly prime, because it can be changed into another prime (25000111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12500205 + 12500206.

It is an arithmetic number, because the mean of its divisors is an integer number (12500206).

Almost surely, 2^25000411 is an apocalyptic number.

25000411 is a deficient number, since it is larger than the sum of its proper divisors (1).

25000411 is an equidigital number, since it uses as much as digits as its factorization.

25000411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40, while the sum is 13.

The square root of 25000411 is about 5000.0410998311. The cubic root of 25000411 is about 292.4033761742.

Adding to 25000411 its reverse (11400052), we get a palindrome (36400463).

The spelling of 25000411 in words is "twenty-five million, four hundred eleven", and thus it is an aban number.