Base | Representation |
---|---|
bin | 100100011000010111100… |
… | …001001110000001000011 |
3 | 22212000002212101212110022 |
4 | 210120113201032001003 |
5 | 311430113240103103 |
6 | 5152303025124055 |
7 | 345423645356441 |
oct | 44302741160103 |
9 | 8760085355408 |
10 | 2500065550403 |
11 | 8842a9910273 |
12 | 344642a8962b |
13 | 1519a8153565 |
14 | 8900a697b91 |
15 | 4507475d138 |
hex | 2461784e043 |
2500065550403 has 2 divisors, whose sum is σ = 2500065550404. Its totient is φ = 2500065550402.
The previous prime is 2500065550387. The next prime is 2500065550487. The reversal of 2500065550403 is 3040555600052.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2500065550403 - 24 = 2500065550387 is a prime.
It is not a weakly prime, because it can be changed into another prime (2500065550603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1250032775201 + 1250032775202.
It is an arithmetic number, because the mean of its divisors is an integer number (1250032775202).
Almost surely, 22500065550403 is an apocalyptic number.
2500065550403 is a deficient number, since it is larger than the sum of its proper divisors (1).
2500065550403 is an equidigital number, since it uses as much as digits as its factorization.
2500065550403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90000, while the sum is 35.
The spelling of 2500065550403 in words is "two trillion, five hundred billion, sixty-five million, five hundred fifty thousand, four hundred three".
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