25001210041 has 2 divisors, whose sum is σ = 25001210042. Its totient is φ = 25001210040.

The previous prime is 25001210029. The next prime is 25001210081. The reversal of 25001210041 is 14001210052.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24031510441 + 969699600 = 155021^2 + 31140^2 .

It is a cyclic number.

It is not a de Polignac number, because 25001210041 - 2⁵ = 25001210009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25001209997 and 25001210024.

It is not a weakly prime, because it can be changed into another prime (25001210081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12500605020 + 12500605021.

It is an arithmetic number, because the mean of its divisors is an integer number (12500605021).

Almost surely, 2^25001210041 is an apocalyptic number.

It is an amenable number.

25001210041 is a deficient number, since it is larger than the sum of its proper divisors (1).

25001210041 is an equidigital number, since it uses as much as digits as its factorization.

25001210041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 80, while the sum is 16.

Adding to 25001210041 its reverse (14001210052), we get a palindrome (39002420093).

The spelling of 25001210041 in words is "twenty-five billion, one million, two hundred ten thousand, forty-one".