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250013483 is a prime number
BaseRepresentation
bin11101110011011…
…10011100101011
3122102110000000122
432321232130223
51003000412413
640450353455
76124036166
oct1671563453
9572400018
10250013483
11119142915
126b88b88b
133ca48895
14252c0add
1516e38108
hexee6e72b

250013483 has 2 divisors, whose sum is σ = 250013484. Its totient is φ = 250013482.

The previous prime is 250013459. The next prime is 250013521. The reversal of 250013483 is 384310052.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 250013483 - 28 = 250013227 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (250013453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125006741 + 125006742.

It is an arithmetic number, because the mean of its divisors is an integer number (125006742).

Almost surely, 2250013483 is an apocalyptic number.

250013483 is a deficient number, since it is larger than the sum of its proper divisors (1).

250013483 is an equidigital number, since it uses as much as digits as its factorization.

250013483 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 26.

The square root of 250013483 is about 15811.8146649902. The cubic root of 250013483 is about 629.9718497542.

The spelling of 250013483 in words is "two hundred fifty million, thirteen thousand, four hundred eighty-three".