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2500141114 = 29901126257
BaseRepresentation
bin1001010100000101…
…0010000000111010
320110020110022212001
42111001102000322
520110014003424
61052030411214
7115645564102
oct22501220072
96406408761
102500141114
1110732a0029
12599360b0a
1330ac7b753
1419a08a202
15e9757844
hex9505203a

2500141114 has 8 divisors (see below), whose sum is σ = 3750620148. Its totient is φ = 1249934400.

The previous prime is 2500141109. The next prime is 2500141117. The reversal of 2500141114 is 4111410052.

It can be written as a sum of positive squares in 2 ways, for example, as 2062703889 + 437437225 = 45417^2 + 20915^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 2500141091 and 2500141100.

It is not an unprimeable number, because it can be changed into a prime (2500141117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43327 + ... + 82930.

Almost surely, 22500141114 is an apocalyptic number.

2500141114 is a deficient number, since it is larger than the sum of its proper divisors (1250479034).

2500141114 is a wasteful number, since it uses less digits than its factorization.

2500141114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 136160.

The product of its (nonzero) digits is 160, while the sum is 19.

The square root of 2500141114 is about 50001.4111200874. The cubic root of 2500141114 is about 1357.2343439722.

Adding to 2500141114 its reverse (4111410052), we get a palindrome (6611551166).

The spelling of 2500141114 in words is "two billion, five hundred million, one hundred forty-one thousand, one hundred fourteen".

Divisors: 1 2 9901 19802 126257 252514 1250070557 2500141114