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250032443140313 is a prime number
BaseRepresentation
bin111000110110011100110110…
…111101001010100011011001
31012210021212102212021121112122
4320312130312331022203121
5230233012420420442223
62243435152455551025
7103444151012135561
oct7066346675124331
91183255385247478
10250032443140313
1172739188902999
1224061b6738b475
13a968c5c2888b2
1445a58c5d25da1
151dd8db70715c8
hexe36736f4a8d9

250032443140313 has 2 divisors, whose sum is σ = 250032443140314. Its totient is φ = 250032443140312.

The previous prime is 250032443140219. The next prime is 250032443140331. The reversal of 250032443140313 is 313041344230052.

Together with next prime (250032443140331) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 145832384427664 + 104200058712649 = 12076108^2 + 10207843^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-250032443140313 is a prime.

It is not a weakly prime, because it can be changed into another prime (250032443140213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125016221570156 + 125016221570157.

It is an arithmetic number, because the mean of its divisors is an integer number (125016221570157).

Almost surely, 2250032443140313 is an apocalyptic number.

It is an amenable number.

250032443140313 is a deficient number, since it is larger than the sum of its proper divisors (1).

250032443140313 is an equidigital number, since it uses as much as digits as its factorization.

250032443140313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 35.

Adding to 250032443140313 its reverse (313041344230052), we get a palindrome (563073787370365).

The spelling of 250032443140313 in words is "two hundred fifty trillion, thirty-two billion, four hundred forty-three million, one hundred forty thousand, three hundred thirteen".