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250065342772681 is a prime number
BaseRepresentation
bin111000110110111011011111…
…111011010011010111001001
31012210102000100200202002202011
4320312323133323103113021
5230234032310222211211
62243502233233135521
7103446424211324242
oct7066733773232711
91183360320662664
10250065342772681
1172751130894707
12240684093ba5a1
13a96c0a32c3297
1445a73274cbcc9
151dd9b90515921
hexe36edfed35c9

250065342772681 has 2 divisors, whose sum is σ = 250065342772682. Its totient is φ = 250065342772680.

The previous prime is 250065342772613. The next prime is 250065342772697. The reversal of 250065342772681 is 186277243560052.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 197082739195456 + 52982603577225 = 14038616^2 + 7278915^2 .

It is a cyclic number.

It is not a de Polignac number, because 250065342772681 - 29 = 250065342772169 is a prime.

It is a super-2 number, since 2×2500653427726812 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (250065342772601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125032671386340 + 125032671386341.

It is an arithmetic number, because the mean of its divisors is an integer number (125032671386341).

Almost surely, 2250065342772681 is an apocalyptic number.

It is an amenable number.

250065342772681 is a deficient number, since it is larger than the sum of its proper divisors (1).

250065342772681 is an equidigital number, since it uses as much as digits as its factorization.

250065342772681 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 33868800, while the sum is 58.

The spelling of 250065342772681 in words is "two hundred fifty trillion, sixty-five billion, three hundred forty-two million, seven hundred seventy-two thousand, six hundred eighty-one".