Base | Representation |
---|---|
bin | 100100011001001100001… |
… | …111110111101111111101 |
3 | 22212002101112000110222022 |
4 | 210121030033313233331 |
5 | 311433421222221242 |
6 | 5152530510125525 |
7 | 345454606622666 |
oct | 44311417675775 |
9 | 8762345013868 |
10 | 2500950195197 |
11 | 884713204a73 |
12 | 34484b1b08a5 |
13 | 151ab9501a0c |
14 | 89091d7836d |
15 | 450c72550d2 |
hex | 2464c3f7bfd |
2500950195197 has 4 divisors (see below), whose sum is σ = 2512803039936. Its totient is φ = 2489097350460.
The previous prime is 2500950195169. The next prime is 2500950195241. The reversal of 2500950195197 is 7915910590052.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2500950195197 - 212 = 2500950191101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2500950195167) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5926422053 + ... + 5926422474.
It is an arithmetic number, because the mean of its divisors is an integer number (628200759984).
Almost surely, 22500950195197 is an apocalyptic number.
It is an amenable number.
2500950195197 is a deficient number, since it is larger than the sum of its proper divisors (11852844739).
2500950195197 is a wasteful number, since it uses less digits than its factorization.
2500950195197 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11852844738.
The product of its (nonzero) digits is 1275750, while the sum is 53.
The spelling of 2500950195197 in words is "two trillion, five hundred billion, nine hundred fifty million, one hundred ninety-five thousand, one hundred ninety-seven".
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