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25012143141 = 310937627979
BaseRepresentation
bin10111010010110101…
…110000010000100101
32101120010202112001220
4113102311300100211
5402211102040031
615253533010553
71543552465056
oct272265602045
971503675056
1025012143141
11a675780387
124a20623a59
132487bc86cb
1412d3c2872d
159b5cc0596
hex5d2d70425

25012143141 has 8 divisors (see below), whose sum is σ = 33380040480. Its totient is φ = 16659503952.

The previous prime is 25012143071. The next prime is 25012143151. The reversal of 25012143141 is 14134121052.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 25012143141 - 211 = 25012141093 is a prime.

It is a super-3 number, since 3×250121431413 (a number of 32 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25012143151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3810711 + ... + 3817268.

It is an arithmetic number, because the mean of its divisors is an integer number (4172505060).

Almost surely, 225012143141 is an apocalyptic number.

It is an amenable number.

25012143141 is a deficient number, since it is larger than the sum of its proper divisors (8367897339).

25012143141 is a wasteful number, since it uses less digits than its factorization.

25012143141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7629075.

The product of its (nonzero) digits is 960, while the sum is 24.

Adding to 25012143141 its reverse (14134121052), we get a palindrome (39146264193).

The spelling of 25012143141 in words is "twenty-five billion, twelve million, one hundred forty-three thousand, one hundred forty-one".

Divisors: 1 3 1093 3279 7627979 22883937 8337381047 25012143141