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250205425433 is a prime number
BaseRepresentation
bin1110100100000101100…
…1111100111100011001
3212220211020122112211122
43221001121330330121
513044410042103213
6310535350335025
724035216011505
oct3510131747431
9786736575748
10250205425433
1197125492437
12405a935a475
131a7957c57c2
14c177c07305
156795d95d08
hex3a4167cf19

250205425433 has 2 divisors, whose sum is σ = 250205425434. Its totient is φ = 250205425432.

The previous prime is 250205425387. The next prime is 250205425441. The reversal of 250205425433 is 334524502052.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125731940569 + 124473484864 = 354587^2 + 352808^2 .

It is a cyclic number.

It is not a de Polignac number, because 250205425433 - 232 = 245910458137 is a prime.

It is a super-2 number, since 2×2502054254332 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 250205425393 and 250205425402.

It is not a weakly prime, because it can be changed into another prime (250205425133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125102712716 + 125102712717.

It is an arithmetic number, because the mean of its divisors is an integer number (125102712717).

Almost surely, 2250205425433 is an apocalyptic number.

It is an amenable number.

250205425433 is a deficient number, since it is larger than the sum of its proper divisors (1).

250205425433 is an equidigital number, since it uses as much as digits as its factorization.

250205425433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144000, while the sum is 35.

Adding to 250205425433 its reverse (334524502052), we get a palindrome (584729927485).

The spelling of 250205425433 in words is "two hundred fifty billion, two hundred five million, four hundred twenty-five thousand, four hundred thirty-three".