Base | Representation |
---|---|
bin | 1011011000110001111010… |
… | …11001101011010011001011 |
3 | 10021122212101201000012221121 |
4 | 11230120331121223103023 |
5 | 11240231313001224221 |
6 | 125131311155220111 |
7 | 5163062425440241 |
oct | 554307531532313 |
9 | 107585351005847 |
10 | 25040689476811 |
11 | 7a84773444788 |
12 | 29850782a7637 |
13 | 10c8433223ba8 |
14 | 627d939aa791 |
15 | 2d6574883a41 |
hex | 16c63d66b4cb |
25040689476811 has 2 divisors, whose sum is σ = 25040689476812. Its totient is φ = 25040689476810.
The previous prime is 25040689476787. The next prime is 25040689476851. The reversal of 25040689476811 is 11867498604052.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 25040689476811 - 217 = 25040689345739 is a prime.
It is a super-2 number, since 2×250406894768112 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 25040689476811.
It is not a weakly prime, because it can be changed into another prime (25040689476851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12520344738405 + 12520344738406.
It is an arithmetic number, because the mean of its divisors is an integer number (12520344738406).
Almost surely, 225040689476811 is an apocalyptic number.
25040689476811 is a deficient number, since it is larger than the sum of its proper divisors (1).
25040689476811 is an equidigital number, since it uses as much as digits as its factorization.
25040689476811 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23224320, while the sum is 61.
The spelling of 25040689476811 in words is "twenty-five trillion, forty billion, six hundred eighty-nine million, four hundred seventy-six thousand, eight hundred eleven".
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