Search a number
-
+
2504104433 is a prime number
BaseRepresentation
bin1001010101000001…
…1001100111110001
320110111220200111122
42111100121213301
520112022320213
61052251352025
7116024352005
oct22520314761
96414820448
102504104433
1110755577a6
1259a752615
1330ba386cc
1419a7dc705
15e9c8bd08
hex954199f1

2504104433 has 2 divisors, whose sum is σ = 2504104434. Its totient is φ = 2504104432.

The previous prime is 2504104381. The next prime is 2504104451. The reversal of 2504104433 is 3344014052.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2397767089 + 106337344 = 48967^2 + 10312^2 .

It is a cyclic number.

It is not a de Polignac number, because 2504104433 - 28 = 2504104177 is a prime.

It is a super-2 number, since 2×25041044332 = 12541078022740502978, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2504104483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1252052216 + 1252052217.

It is an arithmetic number, because the mean of its divisors is an integer number (1252052217).

Almost surely, 22504104433 is an apocalyptic number.

It is an amenable number.

2504104433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2504104433 is an equidigital number, since it uses as much as digits as its factorization.

2504104433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 26.

The square root of 2504104433 is about 50041.0274974445. The cubic root of 2504104433 is about 1357.9511452120.

Adding to 2504104433 its reverse (3344014052), we get a palindrome (5848118485).

The spelling of 2504104433 in words is "two billion, five hundred four million, one hundred four thousand, four hundred thirty-three".