25044120131 has 2 divisors, whose sum is σ = 25044120132. Its totient is φ = 25044120130.

The previous prime is 25044120113. The next prime is 25044120137. The reversal of 25044120131 is 13102144052.

Together with previous prime (25044120113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 25044120131 - 2¹⁸ = 25043857987 is a prime.

It is a super-2 number, since 2×25044120131² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25044120097 and 25044120106.

It is not a weakly prime, because it can be changed into another prime (25044120137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12522060065 + 12522060066.

It is an arithmetic number, because the mean of its divisors is an integer number (12522060066).

Almost surely, 2^25044120131 is an apocalyptic number.

25044120131 is a deficient number, since it is larger than the sum of its proper divisors (1).

25044120131 is an equidigital number, since it uses as much as digits as its factorization.

25044120131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 25044120131 its reverse (13102144052), we get a palindrome (38146264183).

The spelling of 25044120131 in words is "twenty-five billion, forty-four million, one hundred twenty thousand, one hundred thirty-one".