Base | Representation |
---|---|
bin | 1110100101001101000… |
… | …1111110001001111011 |
3 | 212221121010221221010210 |
4 | 3221103101332021323 |
5 | 13101013330320011 |
6 | 311025222242203 |
7 | 24045520054020 |
oct | 3512321761173 |
9 | 787533857123 |
10 | 250505323131 |
11 | 972697a6a78 |
12 | 40671886363 |
13 | 1a812988b6b |
14 | c1a5991547 |
15 | 67b23846a6 |
hex | 3a5347e27b |
250505323131 has 32 divisors (see below), whose sum is σ = 404836351488. Its totient is φ = 134505653760.
The previous prime is 250505323121. The next prime is 250505323153. The reversal of 250505323131 is 131323505052.
It is not a de Polignac number, because 250505323131 - 26 = 250505323067 is a prime.
It is a super-2 number, since 2×2505053231312 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (250505323121) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 353505 + ... + 791186.
It is an arithmetic number, because the mean of its divisors is an integer number (12651135984).
Almost surely, 2250505323131 is an apocalyptic number.
250505323131 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
250505323131 is a deficient number, since it is larger than the sum of its proper divisors (154331028357).
250505323131 is a wasteful number, since it uses less digits than its factorization.
250505323131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1145331.
The product of its (nonzero) digits is 13500, while the sum is 30.
Adding to 250505323131 its reverse (131323505052), we get a palindrome (381828828183).
The spelling of 250505323131 in words is "two hundred fifty billion, five hundred five million, three hundred twenty-three thousand, one hundred thirty-one".
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