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25075412143 = 123120369953
BaseRepresentation
bin10111010110100111…
…000110110010101111
32101201112210220211021
4113112213012302233
5402323301142033
615304113035011
71545251325565
oct272647066257
971645726737
1025075412143
11a6a8464311
124a39855a67
13249804b5a2
1412dc3b7a35
159bb61bb2d
hex5d69c6caf

25075412143 has 4 divisors (see below), whose sum is σ = 25095783328. Its totient is φ = 25055040960.

The previous prime is 25075412137. The next prime is 25075412147. The reversal of 25075412143 is 34121457052.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 25075412143 - 217 = 25075281071 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 25075412099 and 25075412108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25075412147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10183746 + ... + 10186207.

It is an arithmetic number, because the mean of its divisors is an integer number (6273945832).

Almost surely, 225075412143 is an apocalyptic number.

25075412143 is a deficient number, since it is larger than the sum of its proper divisors (20371185).

25075412143 is a wasteful number, since it uses less digits than its factorization.

25075412143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20371184.

The product of its (nonzero) digits is 33600, while the sum is 34.

Adding to 25075412143 its reverse (34121457052), we get a palindrome (59196869195).

The spelling of 25075412143 in words is "twenty-five billion, seventy-five million, four hundred twelve thousand, one hundred forty-three".

Divisors: 1 1231 20369953 25075412143