Base | Representation |
---|---|
bin | 10111010111001010… |
… | …010101101001110011 |
3 | 2101202012012011002221 |
4 | 113113022111221303 |
5 | 402333132214201 |
6 | 15305043021511 |
7 | 1545422663461 |
oct | 272712255163 |
9 | 71665164087 |
10 | 25084648051 |
11 | a7026a23a1 |
12 | 4a4096a897 |
13 | 2499c33418 |
14 | 12dd6dd831 |
15 | 9bc3434a1 |
hex | 5d7295a73 |
25084648051 has 2 divisors, whose sum is σ = 25084648052. Its totient is φ = 25084648050.
The previous prime is 25084648021. The next prime is 25084648063. The reversal of 25084648051 is 15084648052.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 25084648051 - 25 = 25084648019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 25084647989 and 25084648007.
It is not a weakly prime, because it can be changed into another prime (25084648021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12542324025 + 12542324026.
It is an arithmetic number, because the mean of its divisors is an integer number (12542324026).
Almost surely, 225084648051 is an apocalyptic number.
25084648051 is a deficient number, since it is larger than the sum of its proper divisors (1).
25084648051 is an equidigital number, since it uses as much as digits as its factorization.
25084648051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 307200, while the sum is 43.
Subtracting from 25084648051 its reverse (15084648052), we obtain a palindrome (9999999999).
The spelling of 25084648051 in words is "twenty-five billion, eighty-four million, six hundred forty-eight thousand, fifty-one".
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