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251015131140240 = 24353761900751449
BaseRepresentation
bin111001000100110000000011…
…101110011001000010010000
31012220202210221002010022110210
4321010300003232121002100
5230400112442032441430
62245510432002124120
7103605146644254315
oct7104600356310220
91186683832108423
10251015131140240
1172a87a12639a05
12241a04b7650640
13aa0a818a211bc
1445db2a9074d0c
151e0472da312b0
hexe44c03b99090

251015131140240 has 320 divisors, whose sum is σ = 812385154022400. Its totient is φ = 64052216709120.

The previous prime is 251015131140181. The next prime is 251015131140269. The reversal of 251015131140240 is 42041131510152.

It is a super-3 number, since 3×2510151311402403 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 251015131140198 and 251015131140207.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4878886036 + ... + 4878937484.

It is an arithmetic number, because the mean of its divisors is an integer number (2538703606320).

Almost surely, 2251015131140240 is an apocalyptic number.

251015131140240 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 251015131140240, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (406192577011200).

251015131140240 is an abundant number, since it is smaller than the sum of its proper divisors (561370022882160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

251015131140240 is a wasteful number, since it uses less digits than its factorization.

251015131140240 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60570 (or 60564 counting only the distinct ones).

The product of its (nonzero) digits is 4800, while the sum is 30.

Adding to 251015131140240 its reverse (42041131510152), we get a palindrome (293056262650392).

The spelling of 251015131140240 in words is "two hundred fifty-one trillion, fifteen billion, one hundred thirty-one million, one hundred forty thousand, two hundred forty".