Base | Representation |
---|---|
bin | 1011011010101000011011… |
… | …00011110100110001101011 |
3 | 10021212221121121202202011001 |
4 | 11231110031203310301223 |
5 | 11242302112200341024 |
6 | 125220432244415431 |
7 | 5200504144366243 |
oct | 555241543646153 |
9 | 107787547682131 |
10 | 25104311340139 |
11 | 7aa9751313319 |
12 | 29954730a7577 |
13 | 1101432147775 |
14 | 62b0ab4a0b23 |
15 | 2d804a066244 |
hex | 16d50d8f4c6b |
25104311340139 has 2 divisors, whose sum is σ = 25104311340140. Its totient is φ = 25104311340138.
The previous prime is 25104311340103. The next prime is 25104311340191. The reversal of 25104311340139 is 93104311340152.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 25104311340139 - 227 = 25104177122411 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 25104311340098 and 25104311340107.
It is not a weakly prime, because it can be changed into another prime (25104311340239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12552155670069 + 12552155670070.
It is an arithmetic number, because the mean of its divisors is an integer number (12552155670070).
Almost surely, 225104311340139 is an apocalyptic number.
25104311340139 is a deficient number, since it is larger than the sum of its proper divisors (1).
25104311340139 is an equidigital number, since it uses as much as digits as its factorization.
25104311340139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 37.
The spelling of 25104311340139 in words is "twenty-five trillion, one hundred four billion, three hundred eleven million, three hundred forty thousand, one hundred thirty-nine".
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