25105433 has 2 divisors, whose sum is σ = 25105434. Its totient is φ = 25105432.

The previous prime is 25105429. The next prime is 25105439. The reversal of 25105433 is 33450152.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24970009 + 135424 = 4997^2 + 368^2 .

It is a cyclic number.

It is not a de Polignac number, because 25105433 - 2² = 25105429 is a prime.

It is a super-2 number, since 2×25105433² = 1260565532234978, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 25105399 and 25105408.

It is not a weakly prime, because it can be changed into another prime (25105439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12552716 + 12552717.

It is an arithmetic number, because the mean of its divisors is an integer number (12552717).

Almost surely, 2^25105433 is an apocalyptic number.

It is an amenable number.

25105433 is a deficient number, since it is larger than the sum of its proper divisors (1).

25105433 is an equidigital number, since it uses as much as digits as its factorization.

25105433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1800, while the sum is 23.

The square root of 25105433 is about 5010.5322072610. The cubic root of 25105433 is about 292.8122479436.

Adding to 25105433 its reverse (33450152), we get a palindrome (58555585).

The spelling of 25105433 in words is "twenty-five million, one hundred five thousand, four hundred thirty-three".