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25114213052657 is a prime number
BaseRepresentation
bin1011011010111010110111…
…01111110111000011110001
310021220220011200120212012022
411231131123233313003301
511242432402020141112
6125225151000441225
75201304416510621
oct555353357670361
9107826150525168
1025114213052657
1180029725a6503
122997377179215
13110234c670a61
1462b76a55a881
152d84294abd72
hex16d75bbf70f1

25114213052657 has 2 divisors, whose sum is σ = 25114213052658. Its totient is φ = 25114213052656.

The previous prime is 25114213052653. The next prime is 25114213052683. The reversal of 25114213052657 is 75625031241152.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19942664049841 + 5171549002816 = 4465721^2 + 2274104^2 .

It is a cyclic number.

It is not a de Polignac number, because 25114213052657 - 22 = 25114213052653 is a prime.

It is not a weakly prime, because it can be changed into another prime (25114213052653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12557106526328 + 12557106526329.

It is an arithmetic number, because the mean of its divisors is an integer number (12557106526329).

Almost surely, 225114213052657 is an apocalyptic number.

It is an amenable number.

25114213052657 is a deficient number, since it is larger than the sum of its proper divisors (1).

25114213052657 is an equidigital number, since it uses as much as digits as its factorization.

25114213052657 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504000, while the sum is 44.

The spelling of 25114213052657 in words is "twenty-five trillion, one hundred fourteen billion, two hundred thirteen million, fifty-two thousand, six hundred fifty-seven".