Base | Representation |
---|---|
bin | 1011011010111010110111… |
… | …01111110111000011110001 |
3 | 10021220220011200120212012022 |
4 | 11231131123233313003301 |
5 | 11242432402020141112 |
6 | 125225151000441225 |
7 | 5201304416510621 |
oct | 555353357670361 |
9 | 107826150525168 |
10 | 25114213052657 |
11 | 80029725a6503 |
12 | 2997377179215 |
13 | 110234c670a61 |
14 | 62b76a55a881 |
15 | 2d84294abd72 |
hex | 16d75bbf70f1 |
25114213052657 has 2 divisors, whose sum is σ = 25114213052658. Its totient is φ = 25114213052656.
The previous prime is 25114213052653. The next prime is 25114213052683. The reversal of 25114213052657 is 75625031241152.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19942664049841 + 5171549002816 = 4465721^2 + 2274104^2 .
It is a cyclic number.
It is not a de Polignac number, because 25114213052657 - 22 = 25114213052653 is a prime.
It is not a weakly prime, because it can be changed into another prime (25114213052653) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12557106526328 + 12557106526329.
It is an arithmetic number, because the mean of its divisors is an integer number (12557106526329).
Almost surely, 225114213052657 is an apocalyptic number.
It is an amenable number.
25114213052657 is a deficient number, since it is larger than the sum of its proper divisors (1).
25114213052657 is an equidigital number, since it uses as much as digits as its factorization.
25114213052657 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504000, while the sum is 44.
The spelling of 25114213052657 in words is "twenty-five trillion, one hundred fourteen billion, two hundred thirteen million, fifty-two thousand, six hundred fifty-seven".
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