Base | Representation |
---|---|
bin | 1110100111100101101… |
… | …0100010110000010001 |
3 | 220000020201211012001101 |
4 | 3221321122202300101 |
5 | 13103321121320101 |
6 | 311212515104401 |
7 | 24100416110362 |
oct | 3517132426021 |
9 | 800221735041 |
10 | 251145104401 |
11 | 97567956124 |
12 | 4080bba2101 |
13 | 1a8b53a2869 |
14 | c226931b69 |
15 | 67ed60e401 |
hex | 3a796a2c11 |
251145104401 has 2 divisors, whose sum is σ = 251145104402. Its totient is φ = 251145104400.
The previous prime is 251145104393. The next prime is 251145104423. The reversal of 251145104401 is 104401541152.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 165075627025 + 86069477376 = 406295^2 + 293376^2 .
It is a cyclic number.
It is not a de Polignac number, because 251145104401 - 23 = 251145104393 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 251145104401.
It is not a weakly prime, because it can be changed into another prime (251145104501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125572552200 + 125572552201.
It is an arithmetic number, because the mean of its divisors is an integer number (125572552201).
Almost surely, 2251145104401 is an apocalyptic number.
It is an amenable number.
251145104401 is a deficient number, since it is larger than the sum of its proper divisors (1).
251145104401 is an equidigital number, since it uses as much as digits as its factorization.
251145104401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3200, while the sum is 28.
Adding to 251145104401 its reverse (104401541152), we get a palindrome (355546645553).
The spelling of 251145104401 in words is "two hundred fifty-one billion, one hundred forty-five million, one hundred four thousand, four hundred one".
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