2511753714049 has 2 divisors, whose sum is σ = 2511753714050. Its totient is φ = 2511753714048.

The previous prime is 2511753714031. The next prime is 2511753714059. The reversal of 2511753714049 is 9404173571152.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2510538843024 + 1214871025 = 1584468^2 + 34855^2 .

It is a cyclic number.

It is not a de Polignac number, because 2511753714049 - 2³¹ = 2509606230401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2511753713993 and 2511753714011.

It is not a weakly prime, because it can be changed into another prime (2511753714059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1255876857024 + 1255876857025.

It is an arithmetic number, because the mean of its divisors is an integer number (1255876857025).

Almost surely, 2^{2511753714049} is an apocalyptic number.

It is an amenable number.

2511753714049 is a deficient number, since it is larger than the sum of its proper divisors (1).

2511753714049 is an equidigital number, since it uses as much as digits as its factorization.

2511753714049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1058400, while the sum is 49.

The spelling of 2511753714049 in words is "two trillion, five hundred eleven billion, seven hundred fifty-three million, seven hundred fourteen thousand, forty-nine".