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2512057883 is a prime number
BaseRepresentation
bin1001010110111010…
…1111011000011011
320111001212202120212
42111232233120123
520121041323013
61053134041335
7116152065626
oct22556573033
96431782525
102512057883
111079a9a2a5
125a134924b
133105918aa
1419b8acdbd
15ea80d6a8
hex95baf61b

2512057883 has 2 divisors, whose sum is σ = 2512057884. Its totient is φ = 2512057882.

The previous prime is 2512057871. The next prime is 2512057931. The reversal of 2512057883 is 3887502152.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2512057883 - 212 = 2512053787 is a prime.

It is a super-3 number, since 3×25120578833 (a number of 29 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2512057883.

It is not a weakly prime, because it can be changed into another prime (2512059883) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256028941 + 1256028942.

It is an arithmetic number, because the mean of its divisors is an integer number (1256028942).

Almost surely, 22512057883 is an apocalyptic number.

2512057883 is a deficient number, since it is larger than the sum of its proper divisors (1).

2512057883 is an equidigital number, since it uses as much as digits as its factorization.

2512057883 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 134400, while the sum is 41.

The square root of 2512057883 is about 50120.4337870294. The cubic root of 2512057883 is about 1359.3873182822.

The spelling of 2512057883 in words is "two billion, five hundred twelve million, fifty-seven thousand, eight hundred eighty-three".