Base | Representation |
---|---|
bin | 111001000111101001010011… |
… | …001110000111100101010010 |
3 | 1012221110211022220201122001002 |
4 | 321013221103032013211102 |
5 | 230411342320014244132 |
6 | 2250142044514542002 |
7 | 103625420635212464 |
oct | 7107512316074522 |
9 | 1187424286648032 |
10 | 251214033353042 |
11 | 73054300767361 |
12 | 24212b67597902 |
13 | aa234c6785946 |
14 | 4606b77432134 |
15 | 1e099c090a262 |
hex | e47a53387952 |
251214033353042 has 4 divisors (see below), whose sum is σ = 376821050029566. Its totient is φ = 125607016676520.
The previous prime is 251214033353039. The next prime is 251214033353069. The reversal of 251214033353042 is 240353330412152.
251214033353042 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 209299557561721 + 41914475791321 = 14467189^2 + 6474139^2 .
It is a junction number, because it is equal to n+sod(n) for n = 251214033352987 and 251214033353005.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62803508338259 + ... + 62803508338262.
Almost surely, 2251214033353042 is an apocalyptic number.
251214033353042 is a deficient number, since it is larger than the sum of its proper divisors (125607016676524).
251214033353042 is a wasteful number, since it uses less digits than its factorization.
251214033353042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 125607016676523.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 251214033353042 its reverse (240353330412152), we get a palindrome (491567363765194).
The spelling of 251214033353042 in words is "two hundred fifty-one trillion, two hundred fourteen billion, thirty-three million, three hundred fifty-three thousand, forty-two".
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