Base | Representation |
---|---|
bin | 100100100011100111100… |
… | …001111101111000111011 |
3 | 22220011021201122212022111 |
4 | 210203213201331320323 |
5 | 312124333201421021 |
6 | 5202021425033151 |
7 | 346332206040664 |
oct | 44434741757073 |
9 | 8804251585274 |
10 | 2512145342011 |
11 | 889438610518 |
12 | 346a544857b7 |
13 | 152b819a4646 |
14 | 89834b2636b |
15 | 4552eee08e1 |
hex | 248e787de3b |
2512145342011 has 2 divisors, whose sum is σ = 2512145342012. Its totient is φ = 2512145342010.
The previous prime is 2512145341991. The next prime is 2512145342039. The reversal of 2512145342011 is 1102435412152.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2512145342011 - 221 = 2512143244859 is a prime.
It is not a weakly prime, because it can be changed into another prime (2512145342111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256072671005 + 1256072671006.
It is an arithmetic number, because the mean of its divisors is an integer number (1256072671006).
Almost surely, 22512145342011 is an apocalyptic number.
2512145342011 is a deficient number, since it is larger than the sum of its proper divisors (1).
2512145342011 is an equidigital number, since it uses as much as digits as its factorization.
2512145342011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
It can be divided in two parts, 251214 and 5342011, that added together give a square (5593225 = 23652).
The spelling of 2512145342011 in words is "two trillion, five hundred twelve billion, one hundred forty-five million, three hundred forty-two thousand, eleven".
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