Base | Representation |
---|---|
bin | 1110100111111100100… |
… | …0111001111110110001 |
3 | 220000111102112111221111 |
4 | 3221333020321332301 |
5 | 13104020213103431 |
6 | 311230225353321 |
7 | 24102663330043 |
oct | 3517710717661 |
9 | 800442474844 |
10 | 251241144241 |
11 | 9760709229a |
12 | 40838198841 |
13 | 1a8cc25a979 |
14 | c2355b1a93 |
15 | 6806c807b1 |
hex | 3a7f239fb1 |
251241144241 has 2 divisors, whose sum is σ = 251241144242. Its totient is φ = 251241144240.
The previous prime is 251241144151. The next prime is 251241144293. The reversal of 251241144241 is 142441142152.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 139771299600 + 111469844641 = 373860^2 + 333871^2 .
It is a cyclic number.
It is not a de Polignac number, because 251241144241 - 213 = 251241136049 is a prime.
It is a super-2 number, since 2×2512411442412 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (251241144941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125620572120 + 125620572121.
It is an arithmetic number, because the mean of its divisors is an integer number (125620572121).
Almost surely, 2251241144241 is an apocalyptic number.
It is an amenable number.
251241144241 is a deficient number, since it is larger than the sum of its proper divisors (1).
251241144241 is an equidigital number, since it uses as much as digits as its factorization.
251241144241 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10240, while the sum is 31.
Adding to 251241144241 its reverse (142441142152), we get a palindrome (393682286393).
The spelling of 251241144241 in words is "two hundred fifty-one billion, two hundred forty-one million, one hundred forty-four thousand, two hundred forty-one".
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