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25130043223 = 137993182111
BaseRepresentation
bin10111011001110111…
…100000011101010111
32101212100121110120121
4113121313200131113
5402431242340343
615313344012411
71546513562065
oct273167403527
971770543517
1025130043223
11a72628846a
124a54001107
1324a646887c
141305759035
159c130daed
hex5d9de0757

25130043223 has 4 divisors (see below), whose sum is σ = 25130363328. Its totient is φ = 25129723120.

The previous prime is 25130043217. The next prime is 25130043287. The reversal of 25130043223 is 32234003152.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 25130043223 - 217 = 25129912151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25130443223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46938 + ... + 229048.

It is an arithmetic number, because the mean of its divisors is an integer number (6282590832).

Almost surely, 225130043223 is an apocalyptic number.

25130043223 is a deficient number, since it is larger than the sum of its proper divisors (320105).

25130043223 is a wasteful number, since it uses less digits than its factorization.

25130043223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 320104.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 25130043223 its reverse (32234003152), we get a palindrome (57364046375).

The spelling of 25130043223 in words is "twenty-five billion, one hundred thirty million, forty-three thousand, two hundred twenty-three".

Divisors: 1 137993 182111 25130043223