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25130536513601 is a prime number
BaseRepresentation
bin1011011011011001010001…
…01100111011000001000001
310021222110022022001120222212
411231230220230323001001
511243214314321413401
6125240450433111505
75202423056603021
oct555545054730101
9107873268046885
1025130536513601
11800988978a2a2
12299a5719b8595
131103a5144a59c
1462c47844ba81
152d8a82597dbb
hex16db28b3b041

25130536513601 has 2 divisors, whose sum is σ = 25130536513602. Its totient is φ = 25130536513600.

The previous prime is 25130536513591. The next prime is 25130536513639. The reversal of 25130536513601 is 10631563503152.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24176249794225 + 954286719376 = 4916935^2 + 976876^2 .

It is a cyclic number.

It is not a de Polignac number, because 25130536513601 - 222 = 25130532319297 is a prime.

It is a super-2 number, since 2×251305365136012 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (25130536516601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12565268256800 + 12565268256801.

It is an arithmetic number, because the mean of its divisors is an integer number (12565268256801).

Almost surely, 225130536513601 is an apocalyptic number.

It is an amenable number.

25130536513601 is a deficient number, since it is larger than the sum of its proper divisors (1).

25130536513601 is an equidigital number, since it uses as much as digits as its factorization.

25130536513601 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243000, while the sum is 41.

The spelling of 25130536513601 in words is "twenty-five trillion, one hundred thirty billion, five hundred thirty-six million, five hundred thirteen thousand, six hundred one".