Base | Representation |
---|---|
bin | 1011011011011001010001… |
… | …01100111011000001000001 |
3 | 10021222110022022001120222212 |
4 | 11231230220230323001001 |
5 | 11243214314321413401 |
6 | 125240450433111505 |
7 | 5202423056603021 |
oct | 555545054730101 |
9 | 107873268046885 |
10 | 25130536513601 |
11 | 800988978a2a2 |
12 | 299a5719b8595 |
13 | 1103a5144a59c |
14 | 62c47844ba81 |
15 | 2d8a82597dbb |
hex | 16db28b3b041 |
25130536513601 has 2 divisors, whose sum is σ = 25130536513602. Its totient is φ = 25130536513600.
The previous prime is 25130536513591. The next prime is 25130536513639. The reversal of 25130536513601 is 10631563503152.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 24176249794225 + 954286719376 = 4916935^2 + 976876^2 .
It is a cyclic number.
It is not a de Polignac number, because 25130536513601 - 222 = 25130532319297 is a prime.
It is a super-2 number, since 2×251305365136012 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (25130536516601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12565268256800 + 12565268256801.
It is an arithmetic number, because the mean of its divisors is an integer number (12565268256801).
Almost surely, 225130536513601 is an apocalyptic number.
It is an amenable number.
25130536513601 is a deficient number, since it is larger than the sum of its proper divisors (1).
25130536513601 is an equidigital number, since it uses as much as digits as its factorization.
25130536513601 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 243000, while the sum is 41.
The spelling of 25130536513601 in words is "twenty-five trillion, one hundred thirty billion, five hundred thirty-six million, five hundred thirteen thousand, six hundred one".
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