Base | Representation |
---|---|
bin | 100100100100100000011… |
… | …100101000010101111111 |
3 | 22220020202021110221001211 |
4 | 210210200130220111333 |
5 | 312133312130304401 |
6 | 5202300255545251 |
7 | 346364652422554 |
oct | 44444034502577 |
9 | 8806667427054 |
10 | 2513100244351 |
11 | 889888631804 |
12 | 34708022b227 |
13 | 152ca4781908 |
14 | 898c5894a2b |
15 | 45588c64951 |
hex | 2492072857f |
2513100244351 has 32 divisors (see below), whose sum is σ = 2616491808000. Its totient is φ = 2411985995520.
The previous prime is 2513100244349. The next prime is 2513100244439. The reversal of 2513100244351 is 1534420013152.
It is not a de Polignac number, because 2513100244351 - 21 = 2513100244349 is a prime.
It is a super-2 number, since 2×25131002443512 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2513100244751) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1552253820 + ... + 1552255438.
It is an arithmetic number, because the mean of its divisors is an integer number (81765369000).
Almost surely, 22513100244351 is an apocalyptic number.
2513100244351 is a deficient number, since it is larger than the sum of its proper divisors (103391563649).
2513100244351 is a wasteful number, since it uses less digits than its factorization.
2513100244351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3399.
The product of its (nonzero) digits is 14400, while the sum is 31.
The spelling of 2513100244351 in words is "two trillion, five hundred thirteen billion, one hundred million, two hundred forty-four thousand, three hundred fifty-one".
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