Base | Representation |
---|---|
bin | 1011011011011100000001… |
… | …01010101011101010100001 |
3 | 10021222121010011001101202111 |
4 | 11231232000222223222201 |
5 | 11243230330123241231 |
6 | 125241253112515321 |
7 | 5202504460011544 |
oct | 555560052535241 |
9 | 107877104041674 |
10 | 25132012321441 |
11 | 800a4768465a3 |
12 | 299a9040abb41 |
13 | 1103c2811c26c |
14 | 62c57845485b |
15 | 2d8b1be144b1 |
hex | 16db80aabaa1 |
25132012321441 has 2 divisors, whose sum is σ = 25132012321442. Its totient is φ = 25132012321440.
The previous prime is 25132012321433. The next prime is 25132012321469. The reversal of 25132012321441 is 14412321023152.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 25126760275600 + 5252045841 = 5012660^2 + 72471^2 .
It is a cyclic number.
It is not a de Polignac number, because 25132012321441 - 23 = 25132012321433 is a prime.
It is not a weakly prime, because it can be changed into another prime (25132012321841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12566006160720 + 12566006160721.
It is an arithmetic number, because the mean of its divisors is an integer number (12566006160721).
Almost surely, 225132012321441 is an apocalyptic number.
It is an amenable number.
25132012321441 is a deficient number, since it is larger than the sum of its proper divisors (1).
25132012321441 is an equidigital number, since it uses as much as digits as its factorization.
25132012321441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 25132012321441 its reverse (14412321023152), we get a palindrome (39544333344593).
The spelling of 25132012321441 in words is "twenty-five trillion, one hundred thirty-two billion, twelve million, three hundred twenty-one thousand, four hundred forty-one".
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