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251334404242 = 2125667202121
BaseRepresentation
bin1110101000010010110…
…0101010100010010010
3220000201221000121121121
43222010230222202102
513104213101413432
6311243400312454
724105205121065
oct3520454524222
9800657017547
10251334404242
119765479a979
124086347272a
131a9156816bc
14c243b2a8dc
156810053197
hex3a84b2a892

251334404242 has 4 divisors (see below), whose sum is σ = 377001606366. Its totient is φ = 125667202120.

The previous prime is 251334404231. The next prime is 251334404267. The reversal of 251334404242 is 242404433152.

251334404242 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 129183455241 + 122150949001 = 359421^2 + 349501^2 .

It is a junction number, because it is equal to n+sod(n) for n = 251334404198 and 251334404207.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62833601059 + ... + 62833601062.

Almost surely, 2251334404242 is an apocalyptic number.

251334404242 is a deficient number, since it is larger than the sum of its proper divisors (125667202124).

251334404242 is a wasteful number, since it uses less digits than its factorization.

251334404242 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 125667202123.

The product of its (nonzero) digits is 92160, while the sum is 34.

Adding to 251334404242 its reverse (242404433152), we get a palindrome (493738837394).

The spelling of 251334404242 in words is "two hundred fifty-one billion, three hundred thirty-four million, four hundred four thousand, two hundred forty-two".

Divisors: 1 2 125667202121 251334404242