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2513439317 = 6833679999
BaseRepresentation
bin1001010111010000…
…0000101001010101
320111011110221120002
42111310000221111
520121420024232
61053223421045
7116166611264
oct22564005125
96434427502
102513439317
11107a853184
125a18b4785
133109565cc
1419bb4c5db
15ea9d2b62
hex95d00a55

2513439317 has 4 divisors (see below), whose sum is σ = 2517120000. Its totient is φ = 2509758636.

The previous prime is 2513439293. The next prime is 2513439319. The reversal of 2513439317 is 7139343152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2513439317 - 224 = 2496662101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2513439319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1839317 + ... + 1840682.

It is an arithmetic number, because the mean of its divisors is an integer number (629280000).

Almost surely, 22513439317 is an apocalyptic number.

It is an amenable number.

2513439317 is a deficient number, since it is larger than the sum of its proper divisors (3680683).

2513439317 is an equidigital number, since it uses as much as digits as its factorization.

2513439317 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3680682.

The product of its digits is 68040, while the sum is 38.

The square root of 2513439317 is about 50134.2130386027. The cubic root of 2513439317 is about 1359.6364579411.

The spelling of 2513439317 in words is "two billion, five hundred thirteen million, four hundred thirty-nine thousand, three hundred seventeen".

Divisors: 1 683 3679999 2513439317